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By evaluating their dot product, find the values of the scalar s for which the two vectors ~b = ˆx + syˆ and ~c = ˆx−syˆ are orthogonal. (Remember that two vectors are orthogonal if and only if their dot product is zero.) Explain your answers with a sketch.

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Answer:


s=\pm 1

Step-by-step explanation:

The dot product of two vectors
\vec{a}=a_1\vec{x}+b_1\vec{y} and
\vec{b}=a_2\vec{x}+b_2\vec{y} is given by


\vec{a}\cdot\vec{b}=a_1\cdot a_2+b_1\cdot b_2

The dot product of two orthogonal vector is always zero thus if
\vec{a}=\vec{x}+s\vec{y} and
\vec{b}=\vec{x}-s\vec{y}, their dot product would be


\vec{a}\cdot\vec{b}=1*1+s*-(s)=1-s^2=0


\implies 1-s^2=0


\implies s^2=1


\implies s=\pm 1

User Leebriggs
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