Question

(Please help this is a test ;-;) The area of a rectangle is 130 millimeters^2. The length is 3 millimeters greater than its width. Let x represent the width of the rectangle. Which equation can be used to solve for x?

A. 3x^2 equals 130


B. x^2 + 3 = 130


C. x (x + 3) = 130


D. (x + 3)^2 = 130

Answer 1

C

Explanation:

L=X+3

LW=130

-substitute X+3 as L:

X(X+3)=130