70.8k views
2 votes
Five students visiting the student health center for a free dental examination during National Dental Hygiene Month were asked how many months had passed since their last visit to a dentist. Their responses were as follows: 6 17 11 22 29 Assuming that these five students can be considered a random sample of all students participating in the free checkup program, construct a 95% confidence interval for the mean number of months elapsed since the last visit to a dentist for the population of students participating in the program.

1 Answer

3 votes

Answer:

A 95% confidence interval for the mean number of months elapsed since the last visit to a dentist, is
[5.79063, 28.20937]

Explanation:

We will build a 95% confidence interval for the mean number of months elapsed since the last visit to a dentist. A (1 -
\alpha) x100% confidence interval for the mean number of months elapsed since the last visit to a dentist with unknown variance and is given by:


[\bar x -T_{(n-1,(\alpha)/(2))} (S)/(√(n)), \bar x +T_{(n-1,(\alpha)/(2))} (S)/(√(n))]


\bar X = 17


n = 5


\alpha = 0.05


T_{(n-1,(\alpha)/(2))}=2.7764


S = 9.0277


[17 -2.7764 (9.0277)/(√(5)), 17 +2.77644 (9.0277)/(√(5))]

A 95% confidence interval for the mean number of months elapsed since the last visit to a dentist, is
[5.79063, 28.20937]

User Dgarbacz
by
6.3k points