Question

At a certain instant, a particle is moving in the direction with momentum 18 kg·m/s. During the next 0.5 s, a constant force <-4, 12, 0> N acts on the particle. What is the momentum of the particle at the end of this 0.5 s interval?

Answer 1

24.325 kg m/s

Step-by-step explanation:

Initial momentum, pi = 18 kg m/s

F = < -4, 12, 0>

t = 0.5 s

Let the final momentum is pf.

The magnitude of force is

`F=\sqrt{(-4)^(2)+12^(2)+0^(2)}=12.65 N`

According to the Newton's second law, the rate of change of momentum is equal to the force.

`F = (p_(f)-p_(1))/(t)`

`12.65= \frac{p_(f)-18}}{0.5}`

pf - 18 = 6.325

pf = 24.325 kg m/s

Thus, the momentum of body after 0.5 s is 24.325 kg m/s.