Question

In a particular experiment at 300 ∘C, [NO2] drops from 0.0100 to 0.00800 M in 100 s. The rate of appearance of O2 for this period is ________ M/s. In a particular experiment at 300 , drops from 0.0100 to 0.00800 in 100 . The rate of appearance of for this period is ________ . 4.0×10−3 2.0×10−3 2.0×10−5 4.0×10−5 1.0×10−5

Answer 1

`1*{10}^(-5)(M)/(s)`

Step-by-step explanation:

The stoichiometry for this reaction is

`2NO_2\rightarrow2NO+O_2`

The rate for this reaction can be written as

`-r_(NO_2)=-(d\left[NO_2\right])/(dt)=((0.01-0.008)M)/(100s)=2*{10}^(-5)(M)/(s)`

This rate of disappearence of
`NO_2` can be realated to the rate of appearence of
`O_2` as follows (the coefficients of each compound are defined by the stoichiometry of the reaction)

`-r_(O_2)=-r_(NO_2)*(coefficient\ O_2\ )/(coefficient\ NO_2)=2*{10}^(-5)(M)/(s)*(1\ mole\ O_2\ )/(2\ mole\ NO_2)=1*{10}^(-5)(M)/(s)`