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A cyclist moving towards right with an acceleration of 4m/s² at t = 0 he has travelled 5 m moving towards the right at 15 m/s what will be his final position

1 Answer

2 votes

Answer:


x=2t^2+15t+5

Step-by-step explanation:


x=(1)/(2)at^2+v_0t+x_0

User Harry Ninh
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