Question

A blood sample with a known glucose concentration of 102.0 mg/dL is used to test a new at home glucose monitor. The device is used to measure the glucose concentration in the blood sample five times. The measured glucose concentrations are 98.4 , 104.3 , 97.4 , 106.7 , and 93.0 mg/dL. Calculate the absolute error and relative error for each measurement made by the glucose monitor.

Answer 1

Step-by-step explanation:

Actual value = 102.0 mg/dL

Calculation of absolute error and relative error for the measured value, 98.4 mg/dL

Absolute error = |Actual value - measured value|

= | 102.0 - 98.4 | = 3.6

Relative error =
`(Absolute\ error)/(Actual\ value)`

=
`(3.6)/(102.0) = 0.03529`

Calculation of absolute error and relative error for the measured value, 104.3 mg/dL

Absolute error = |Actual value - measured value|

= | 102.0 - 104.3 | = 2.3

Relative error =
`(Absolute\ error)/(Actual\ value)`

=
`(2.3)/(102.0) = 0.02255`

Calculation of absolute error and relative error for the measured value, 97.4 mg/dL

Absolute error = |Actual value - measured value|

= | 102.0 - 97.4 | = 4.6

Relative error =
`(Absolute\ error)/(Actual\ value)`

=
`(4.6)/(102.0) = 0.04509`

Calculation of absolute error and relative error for the measured value, 106.7 mg/dL

Absolute error = |Actual value - measured value|

= | 102.0 - 106.7 | = 4.7

Relative error =
`(Absolute\ error)/(Actual\ value)`

=
`(4.7)/(102.0) = 0.04607`

Calculation of absolute error and relative error for the measured value, 93.0 mg/dL

Absolute error = |Actual value - measured value|

= | 102.0 - 93 | = 9

Relative error =
`(Absolute\ error)/(Actual\ value)`

=
`(9)/(102.0) = 0.08823`