Question

Subtract 11b^2-4b+711b 2 −4b+711, b, start superscript, 2, end superscript, minus, 4, b, plus, 7 from b^2+8b-9b 2 +8b−9b, start superscript, 2, end superscript, plus, 8, b, minus, 9.

Answer 1

`-10b^2+12b-16`

Explanation:

Consider the given question is " Subtract
`11b^2-4b+7` from
`b^2+8b-9`".

`(b^2+8b-9)-(11b^2-4b+7)`

Using distributive property we get

`b^2+8b-9-(11b^2)-(-4b)-(7)`

`b^2+8b-9-11b^2+4b-7`

On combining like terms we get

`(b^2-11b^2)+(8b+4b)+(-9-7)`

`-10b^2+12b+(-16)`

`-10b^2+12b-16`

Therefore, the resultant expression is
`-10b^2+12b-16`.