Question

You also learn in class that one kilobyte of computer memory will hold about 2/3 of a page of typical text (without formatting). A typical book has about 400 pages. How many such books can a 9-gig flash drive hold? _______________

Answer 1

The flashdrive can hold 35389 400-pages-books

Step-by-step explanation:

If
`(2)/(3)` of a page occupies 1 kB of memory, we can calculate how much memory a book will take

`2/3kB=1 page\\ x kB=400 pages\\266.67 kB=400 pages`

Now that we know that a book average file size is about 266,67 kB, we calculate how many of them can a 9 GB flash drive hold.

To do the calculation, we have to know how many kilobytes are in 9 gigabytes.

There is 1024 kilobytes in a megabyte, and 1024 megabytes in a gigabyte, so:

`Memory_(in _kilobytes)^{} =1024(kilobytes)/(megabytes) *1024(megabytes)/(gigabytes)*9=9437184 kilobytes`

Finally, knowing the average file size of a book and how much memory in kilobytes the 9 GB flash drive holds, we calculate how many books can it hold.

`Books=(Flash drive memory)/(Filesize of a book) =(9437184kilobytes)/(266.67(kilobytes)/(book) ) =35389,4 books`

The flashdrive can hold 35389 400-pages-books, or 14155776 pages of typical text.