Question

kara borrowed $3650 for one year at an annual interest rate of 16% how much did kara pay in interest show work​

Answer 1

`\bf ~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\dotfill & \$3650\\ r=rate\to 16\%\to (16)/(100)\dotfill &0.16\\ t=years\dotfill &1 \end{cases} \\\\\\ I=(3650)(0.16)(1)\implies I=584`