Answer:
314.92 m
Step-by-step explanation:
Acceleration of the helicopter = 5.4 m/s² = a
Time taken by the helicopter to reach maximum height = 10.8 s = t
Initial velocity = 0 = u
Final velocity = v
Displacement = s
Equation of motion
![s=ut+(1)/(2)at^2\\\Rightarrow s=0* 10.8+(1)/(2)5.4* 10.8^2\\\Rightarrow s=314.92\ m](https://img.qammunity.org/2020/formulas/physics/high-school/afvv0asmttqr8oq69weed83jy62g2eb133.png)
Maximum height above ground reached by the helicopter is 314.92 m