Question

A particle starts at the origin and moves away from it in a straight line. After 1.6 seconds, it is 12.8 meters from the origin. It then reverses direction due to a force field with a like charge. After 3.8 seconds total, the particle is at −9.23 m. What is the average velocity of the particle? 3.8 m/s −5.8 m/s −2.4 m/s 13.8 m/s

Answer 1

Average velocity of the particle is
`-2.4 m/s`

Step-by-step explanation:

Average velocity is defined as the total velocity divided by the total time. It is given by the equation
`v_av= (displacement)/((total time taken))`

In the given problem the particle starts from origin, travels
`12.8 m` and then reverses direction and travels till
`-9.23 m` within a total time of
`3.8 seconds.`

Displacement is defines as the shortest distance between initial and final point.

Here displacement =
`- 9.23 m`

total time=
`3.8 s`

`v_av=-9.23/3.8=-2.4 m/s`