Answer:



Explanation:
From the relations stablished in the problem we have the following equation system:
(equation 1)
(equation 2)
(equation 3)
From equation 1 we can find an expression of
in terms of
which we're going to call equation 4

(equation 4)
We can then replace the equation 4 in the equation 2 in order to find an expression of
in terms of




(here we replaced the eq.4)




(equation 5)
Now, we can replace equations 4 & 5 inside the equation 3 so we can find the value of












This is a quadratic equation which has the form

where



Then, we can find the solutions to this quadratic equation using the well-know quadatric formula which says that
±

then, replacing the values of a, b and c we find the values of z




We have two possible values of z, but because we're trying to find the measure of trapezoid's height the result shouldn't be negative, so we keep only the positive value of z, then

Now we may replace this value of z in the equations 4 & 5 in order to find the values of x & y.
(equation 4)


(equation 5)


So we've found the values of x, y, and z.


