Question

In the previous question, the person had an initial velocity of 8m/s and a constant acceleration of −4m/s2. How would the maximum distance he travels to the right of the origin change if instead his initial velocity were doubled (vx,0=16m/s)?

Answer 1

Distance maximum

Xmax = 32m

Step-by-step explanation:

Kinematics equation between velocities and distance:

`Vf^(2) =Vo^(2) +2ax`

For the distance maximum the final velocity is zero:

`x = Xmax` ⇒
`Vf=0`

then, the equation becomes:

`Xmax= - (Vo^(2))/(2a)`

We replace the values for the initial velocity and acceleration

Vo=16m/s; a = -4m/s2

Finally:

`Xmax=16^(2) /8=32m`