Answer:
- M = 2.294 mol / liter (four significant figures)
Step-by-step explanation:
The molar concentration is calculated as the ratio of solute moles to liters of solution:
- M = number of moles of solute / volume of solution in liters.
The volume of the solution is the given in mililiters, 127.53 ml, so you have to convert it to liters:
- 127.53 ml × 1 liter / 1,000 ml = 0.12753 liter
The moles of solute is calcuated using the molar mass and the formula:
- moles = mass in grams / molar mass
The molar mass of sodium hydroxide (NaOH) is 39.997 g/mol
The mass in grams of the sodium hydroxide solution is calculated by difference:
- mass of sodium hydroxide = mass of the cylinder with the sodium hydroxide added - mass of empty cylinder
- mass of sodium hydroxide = 13.195 g - 1.50 g = 11.695 g
Using the rule for signficant figures, when subtracting measures, that mass must be rounded to two decimal places, which is the least number of decimals of the amounts being subtracted, so the mass of sodium hydroxide is 11.70 g.
- mass of sodium hydroxide = 11.70g (4 signficant digits)
Then,
- n = 11.70 g / 39.997 g/mol ≈ 0.2925 mol
Compute the molarity:
- M = [ 11.70 g / 39.997 mol ] / 0.12753 liter
= 2.294mol / liter ← answer
Note: I divided directly [ 11.70 / 33.997] by 0.12753, instead of 0.2925 by 0.12753, to avoid intermediate roundings that may change the last signficant digit.