Question

Two point charges are separated by a distance of 30.0 cm. The numerical value of one charge is twice that of the other. Each charge exerts a force of magnitude 65.0 N on the other.

Find the magnitude of the charge with a greater magnitude.

Answer 1

The charge with greater magnitude =
`3.60* 10^(-5)C`

Step-by-step explanation:

We have the distance between two charges = 30 cm = 0.3 m

Force between two charges = 65 N

Let the first charge be q

Then according to question second charge will be 2q

According to coulombs law force between two charges

`F=(Kq_1q_2)/(r^2)`

Where K is constant which value is
`K=9* 10^9`

So
`65=(9* 10^9* 2q^2)/(0.3^2)`

`q^2=3.25* 10^(-10)`

`q=1.80* 10^(-5)C`

So larger charge
`2q=2* 1.80* 10^(-5)=3.60* 10^(-5)C`