Answer:
The probability that a combined sample from six public swimming areas will reveal the presence of bacteria = 0.02376
Explanation:
As per the given question
We have given that from six public swimming pools, the probability of finding bacteria in a swimming pool = 0.004
Therefore,
P(Swimming pool has bacteria ) = 0.004
P(That swimming pool does not show the presence of Bacteria) = 1 - 0.004 = 0.996
Probability that all six pools test negative


= 0.97624
Probability that at least one pool tests positive
= 1 - 0.97624
= 0.02376
Therefore,
The probability that a combined sample from six public swimming areas will reveal the presence of bacteria = 0.02376
Yes the probability is low enough so that further testing of the individual samples is rarely necessary.