Answer:
The answer depends on what the problem really is.
f(1/2) = 8
or
f(1/2) = 4
See below.
Explanation:
This is the problem as it was posted:
y = f(x) = 16x
Let x = 1/2
y = f(1/2) = 16(1/2) = 8
Perhaps the problem is this:
![y = f(x) = 16^x](https://img.qammunity.org/2020/formulas/mathematics/college/e9xrkemye9kacg26xkly2k3n9hsveyww8a.png)
If x is an exponent of 16 and not a factor, then the answer is:
![y = f((1)/(2)) = 16^(1)/(2) = √(16) = 4](https://img.qammunity.org/2020/formulas/mathematics/college/cxyal3fvma7cn8do3h5m9zmv9dtssdazm4.png)