Question

A window washer drops a brush from a scaffold on a tall office building. What is the speed of the falling brush after 3.28 s? (Neglect drag forces.) The acceleration due to gravity is 9.8 m/s^2. Answer in units of m/s.

Answer 1

The speed of brush is 32.144 m/s.

Step-by-step explanation:

Given that,

Time = 3.28 s

We need to calculate the speed

Using equation of motion

`v = u+gt`

Where, v = final velocity

u = initial velocity

g = acceleration due to gravity

Put the value into the formula

`v = 0+9.8*3.28`

`v =32.144\ m/s`

Hence, The speed of brush is 32.144 m/s.

Answer 2

The speed of washer will be 32.144 m/s

Step-by-step explanation:

Given that

time t= 3.28 s

Acceleration due to gravity

`g=9.8\ (m)/(s^2)`

Here acceleration is constant so we cam apply the motion equation

we know that

v= u + at

At initial condition u =0 m/s

v= u + at

v= 0 + 9.8 x 3.28

v= 32.144 m/s

So the speed of washer will be 32.144 m/s