Question

The linear momentum of 100.0 kg object moving around a 30.0m circle at a constant speed of 2.20 m/s is

Answer 1

`\boxed{p=220kg.(m)/(s)}`

Step-by-step explanation:

Newton’s second law says that the net force
`\Sigma \vec{F}` acting on a particle equals the time rate of change of the product of the particle’s mass and velocity. This product is called the momentum, or linear momentum. In this problem we know that:

`m=100.0kg \\ \\ v=2.20m/s \\ \\ r=30.3m`

So the momentum is:

`p=mv \\ \\ p=(100.0)(2.20) \\ \\ \boxed{p=220kg.(m)/(s)}`