Question

What is the area trapezoid ABCD A(-1,5) B(3,2) C(0,-2) D(-13,-11)

Answer 1

62.5

Explanation:

slope of AB = (5-2)/(-1 - 3) = -3/4

slope of BC = (2 - -2)/(3-0) = 4/3

AB ⊥ BC (slope -3/4 vs 4/3)

seg AB = √(-1 - 3)² + (5 - 2)² = √25 = 5

seg BC = √(3 - 0)² + (2 - -2)² = √25 = 5

seg AD = √(-1 - -13)² + (5 - -11)² = √400 = 20

Area (BC + AD) * AB / 2 = (5 + 20) * 5 / 2 = 62.5