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How many titanium stoms does it contain when titanium has a density of 4.50g/cm^3

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Answer:

number of atoms = 1.993 x 10^25 atoms

Step-by-step explanation:

please check the attached photo of the complete question

To get the number of atoms we need to get first the mass of titanium by using this formula :

mass = density * volume

the volume of the cube = length^3

1 inch = 2.54 centimeters

2.78 inch = ??

length in cm = 2.54 * 2.78 = 7.0612 cm

so the volume = length^3 = 7^3 = 352.07528346 cm^3

bs substitution in mass formula:

when density = 4.5 g/cm and volume =352.07528346 Cm^

mass = 4.5 * 352.07528346 = 1584.33877557 g

the number of atoms = mass / molar mass * avogadro's number(constant)

= (1584.33877557/47.867 )* 6.02 * 10^23

= 33.0988 * (6.02*10^23) atoms

=1.993 x 10^25 atoms

How many titanium stoms does it contain when titanium has a density of 4.50g/cm^3-example-1
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