Question

Consider a runner traveling with an initial velocity of 1.9 m/s in the positive direction accelerates at a constant rate of 1.2 m/s2 for a time of 3 seconds. What is his velocity at the end of this time?

Answer 1

Answer: 5.5 m/s

Step-by-step explanation:

As we are told the runner accelerates at a constant rate, we can use the following equation:

`V_(f)=V_(o) + at`

Where:

`V_(f)` is the runner's final velocity

`V_(o)=1.9 m/s` is the runner's initial velocity

`a=1.2 m/s^(2)` is the runner's constant acceleration

`t=3 s` is the time it takes the runner to reach the final velocity

`V_(f)=1.9 m/s +(1.2 m/s^(2))(3 s)`

Finally:

`V_(f)=5.5 m/s`