Answer:
The amount invested in the account that paid 8.2% is $4,000 and the amount invested in the account that paid 21.5% is $2,000
Explanation:
Let
2x -----> the amount invested in the account that paid 8.2%
x -----> the amount invested in the account that paid 21.5%
in this problem we have
![8.2\%=8.2/100=0.082\\21.5\%=21.5/100=0.215](https://img.qammunity.org/2020/formulas/mathematics/college/2au9pjv48ffr24wa2qottpdauuej38kb3r.png)
we know that
![2x(0.082)+x(0.215)=758](https://img.qammunity.org/2020/formulas/mathematics/college/ivqpew2hpy2pqs7cnwr3ar8r6887cnwn5p.png)
Solve for x
![0.164x+0.215x=758](https://img.qammunity.org/2020/formulas/mathematics/college/y1h73e08uix9ucqduqquawiozdxcd7g0wy.png)
![0.379x=758](https://img.qammunity.org/2020/formulas/mathematics/college/8q73i26luyf0dsibu7ea8axrgd3n3jht8n.png)
![x=\$2,000](https://img.qammunity.org/2020/formulas/mathematics/college/l442sgv18po5sc4s7iaeouyfdk750vd0wm.png)
so
![2x=\$4,000](https://img.qammunity.org/2020/formulas/mathematics/college/uup1a90ihza9gumuxcwfg1kiq2f986ziv3.png)
therefore
The amount invested in the account that paid 8.2% is $4,000 and the amount invested in the account that paid 21.5% is $2,000