Question

Solve the equation on the interval [0, 2π).

tan^2x sin x = tan^2x

A. π/2, π
B. 0, π/2
C. 0, π
D. π/2, 2π

Answer 1

x = pi/2..only

Explanation:

The equation states that...,

tan^2x.sin x = tan^2x

;we simplify the equation by dividing both sides by tan^2x...which then leaves our equation as,

; sin x = 1

; x = sin^-1 (1)

; Hence x = pi/2