Question

X=year

y= amount

In 2008 Liam purchased a house for $156,000.00

In 2019 Liam house is worth $250,000.00

What is the increase of Liams vaule of his house after 11 years?

Find the slope?

Formula = y2-y1/ x2-x1 =_____________

Answer 1

The value of house increased by $94,000.00.

The value of slope is
`(94000)/(11)`. It can be written as
`8545.\overline {45}`.

Explanation:

Given information:

The worth of house in 2019 = $250,000.00

The worth of house in 2008 = $156,000.00

Let y be the worth of house after x years. It means the two points are (2008,156000) and (2019, 250000).

The amount by which the value of house increases in 11 years is

`Increase=$250,000.00-$156,000.00=$$250,000.00-$94,000.00`

In 11 years, the value of house increased by $94,000.00.

The formula for slope is

`slope=(y_2-y_1)/(x_2-x_1)`

Two points are (2008,156000) and (2019, 250000). So, the slope is

`slope=(250000-156000)/(2019-2008)`

`slope=(94000)/(11)`

`slope=8545.45454545`

`slope=8545.\overline {45}`

Therefore the value of slope is
`(94000)/(11)`. It can be written as
`8545.\overline {45}`.