Answer:
a)
![y=4x-160](https://img.qammunity.org/2020/formulas/mathematics/college/984uw28zf0z96fh3saqe114lhtyh570qwy.png)
b)
![y=4(102)-160=248(chirps)/(min)](https://img.qammunity.org/2020/formulas/mathematics/college/jz5w7ql3wu2lg8mu4r05s2necz6kkif0db.png)
Explanation:
We know that theres a linear relationship between the rate of the chirping of crickets and the air temperature.
The equation of a line is:
![y=mx+b](https://img.qammunity.org/2020/formulas/mathematics/high-school/8nudzfk4b5l0arb9iixag2w8am6zn99zlr.png)
So, let's name our variables
x= Temperature
y=Rate of the chirping
First of all, we need to find the slope with the two given points
60ºF ,
![y_(1) =80(chirps)/(min)](https://img.qammunity.org/2020/formulas/mathematics/college/rajr6ybi2j88teij2wba4f3m6erqsx3hjr.png)
80ºF,
![y_(2) =160(chirps)/(min)](https://img.qammunity.org/2020/formulas/mathematics/college/dpj7u0w0nwj5btb3q9s1ges6bn6vnzi7er.png)
By,
![m=(y_(2)-y_(1) )/(x_(2)-x_(1) ) =(160-80)/(80-60)](https://img.qammunity.org/2020/formulas/mathematics/college/nrerxrn9lyswgvh5lnrphcnrttixdjhpah.png)
![m=4](https://img.qammunity.org/2020/formulas/mathematics/high-school/xpv5828ne56hdaq021276ipjbtebr3swor.png)
Now, the equation between the air temperature and the number of chirps is:
![y-y_(1) =m(x-x_(1) )](https://img.qammunity.org/2020/formulas/mathematics/high-school/xhoy6za6b2conuogs78rk91qnxe8hl0sph.png)
![y-80=4(x-60)](https://img.qammunity.org/2020/formulas/mathematics/college/upmurdnscgfsdfyv0wgm17k17ycjt443pq.png)
Solving for y,
a)
![y=4x-160](https://img.qammunity.org/2020/formulas/mathematics/college/984uw28zf0z96fh3saqe114lhtyh570qwy.png)
b) To calculate the rate at which the crickets chirp when the temperature is 102 ºF we need to evaluate y(102)
![y=4(102)-160=248(chirps)/(min)](https://img.qammunity.org/2020/formulas/mathematics/college/jz5w7ql3wu2lg8mu4r05s2necz6kkif0db.png)