Question

C=(0.088)(4)kA(N-1)/N, solve for A in variable form answer

Answer 1

`A=(1)/(k)\log_4((CN)/((N-1)(0.088)))`

Explanation:

Given formula,

`C=(0.088)(4)^(kA) ((N-1))/(N)----(1)`

For finding the formula for A we need to isolate A in the left side,

From equation (1),

`C=((0.088)(N-1))/(N)4^(kA)`

`(CN)/((0.088)(N-1))=4^(kA)`

Taking log both sides,

`\log((CN)/((0.088)(N-1)))=kA \log 4`

`\implies A=(\log((CN)/((0.088)(N-1))))/(log 4)`

`\implies A=(1)/(k)\log_4((CN)/((N-1)(0.088)))`

`(\because \log_bx=(\log_ax)/(\log_ab))`