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Verify that quadrilateral BCDE is a rhombus with vertices B(5, -1), C(-2, 0), D( -1, 7) and E(6, 6) by showing that all four sides are equal.

A. BD = CE = √50

B. BD = CE = 50

C. BC = CD = DE = EB = 50

D. BC = CD = DE = EB = √50

User Svandragt
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1 Answer

4 votes

Answer:

The right answer to your question is: D = √50

Explanation:

We need to use the formula of distance between to points

√(x2-x1)² - (y2-y1)²

√(-2-5)² +(0+1)² = √50 = √ (-7)² + (1)² = √49 + 1

√(-1+2)² + (7-0)² = √50 = √ 1² + 7² = √1 + 49 = √50

√(6+1)² + (6-7)² = √50

√(6-5)² + (6+1)² = √50

User Parisni
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