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What mass error (in mg, round to the nearest tenth) would occur in the weighing of 450 mg of a drug if the uncalibrated balance created a 15 % error in all measurements?

User Sitems
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1 Answer

3 votes

Answer: 67.5

Explanation:

Given: The mass of drug = 450 mg

The mass percent error = 15%

Which can be written as 0.15.

We use the formula :-


\text{Error}=\text{Previous value }*\text{Percent error}

Similarly,
\text{Mass Error}=\text{Mass of drug }*\text{Mass percent error}


\Rightarrow\ \text{Mass Error}=450*0.15=67.5\ mg

Hence, the mass error would be 67.5 mg.

User Gyozo Kudor
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