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Find all the square roots of x^2 ≡ 53 (mod 77) by hand. This is my second post. Please explain all the steps how you did this?

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Answer:

Explanation:

Given that


x^2 ≡ 53 (mod 77)

Right side has values as

53, 53+77, 53+2(77),+....

We have to find one which is a perfect square.

We have from this series 361 is 19 square

Thus
x =19.

Next is
x^2=900\\x=30


x^2=2209\\x=47 and so on.

User Townsfolk
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