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16.4.57 Question Help A box contains eighteen $1 bills, ten $5 bills, eight $10 bills, three $20 bills, and one $100 bill You blindly reach into the box and draw a bill at random What is the expected value of your draw? The expected value of the draw is SL (Round to the nearest cent)

User DLiKS
by
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1 Answer

2 votes

Answer:

$ 7.7

Explanation:

Given,

There are 18 $1 bills, ten $5 bills, eight $10 bills, three $20 bills, and one $100 bill,

Total number of bills = 18 + 10 + 8 + 3 + 1 = 40,


\because \text{Probability}=\frac{\text{Favourable outcomes}}{\text{Total outcomes}}

Thus,

The probability of $ 1 =
(18)/(40)

The probability of $ 5 =
(10)/(40)

The probability of $ 10 =
(8)/(40)

The probability of $ 20 =
(3)/(40)

The probability of $ 100 =
(1)/(40)

If a bill is selected randomly,

The expected value of the bill


=(18)/(40)* 1+(10)/(40)* 5+(8)/(40)* 10+(3)/(40)* 20+(1)/(40)* 100


=(18+50+80+60+100)/(40)


=(308)/(40)

= $ 7.7

User Oscar Del Ben
by
5.9k points