Answer:
(a). The average current flows through the dryer is 12.5 A
(b). The resistance of the dryer is 9.6 Ω
Step-by-step explanation:
Given that,
Voltage = 120 V
Power = 1500 W
(a). We need to calculate the average current flows through the dryer
Using formula of current


Where, P = power
V = voltage
Put the value into the formula


(b). We need to calculate the resistance of the dryer
Using Ohm's law


Where, I = current
Put the value into the formula


Hence, (a). The average current flows through the dryer is 12.5 A
(b). The resistance of the dryer is 9.6 Ω