Question

A series R-L-C circuit is connected to a 110 Hz ac source that has Vrms = 80.0 V . The circuit has a resistance of 65.0 Ω and an impedance of 104 Ω at this frequency. What average power is delivered to the circuit by the source?

Answer 1

Power P =38.46 W

Step-by-step explanation:

We have given the voltage
`V_(rms)=80V`

Resistance R = 65 ohm

Impedance Z = 104 ohm

According to ohm's law current
`i=(V)/(Z)=(80)/(104)=0.7692A`

Power factor
`cos\Phi =(R)/(Z)=(65)/(104)=0.625`

Power delivered by the source P
`Vicos\Phi =80* 0.7692* 0.625=38.46W`