Answer:
Step-by-step explanation:
We shall apply Bernouli's theorem
ρgh + 1/2 ρ v² + P = constant
ρ is density of fluid ( here it is air ) v is velocity of air , P is pressure of air
For h to be constant
1/2 ρ v² + P = constant
1/2 ρ₁ v₁² + P₁ = 1/2 ρ₂ v₂² + P₂
P₂ -P₁ = 1/2 ρ₁ v₁² - 1/2 ρ₂ v₂²
P₂ -P₁ = Pressure difference = 20 x 32
ρ₁ and ρ₂ are same here and is equal to .07967 lb/ft³
Putting the values we get
20 x 32 = 1/2 x .07967 ( v₁² -v₂² )
( v₁² -v₂² ) = 16066
v₂ = 350 ft/s
v₁²-350² = 16066
122500 + 16066 = v₁²
v₁² = 138566
v₁ = 372 ft/s
[ At lower wing velocity will be lower so that pressure will be higher.]