Answer:
Time taken by the spacecraft to cross milky way,
![T = 6.147* 10^(4) years](https://img.qammunity.org/2020/formulas/physics/college/eo5jjiczqsnlfsm1s65ufi8kc7vvyebwfg.png)
Given:
Actual length, l =
![1.2* 10^(5) ly](https://img.qammunity.org/2020/formulas/physics/college/12ctcwxxxdrde1ai426wzybxlwhrtd437l.png)
speed of the aircraft, v =0.890 c
Solution:
From the Einstein's theory of relativity, using length contraction:
![l' = l\sqrt(1 - (v^(2))/(c^(2)))](https://img.qammunity.org/2020/formulas/physics/college/kkm4pavonx1gdi4e7uh0e4gfk7dk9i3b0l.png)
![l' = 1.2* 10^(5)\sqrt(1 - ((0.890 c)^(2))/(c^(2)))](https://img.qammunity.org/2020/formulas/physics/college/ycszaoclmwfp9iv637f2svnheq8e2rn5tr.png)
l' =
![5.472* 10^(4) ly = 5.472* 10^(4)c yrs](https://img.qammunity.org/2020/formulas/physics/college/s8gkucjna9lgvzqkc80luckqtvazaq9le6.png)
Time taken by the spacecraft to cross milky way, T:
![T = (l')/(v)](https://img.qammunity.org/2020/formulas/physics/college/zd127qbs3r5q5l47xw47l8hqyhy0ybb8z5.png)
![T = ( 5.472* 10^(4)c)/(0.890 c)](https://img.qammunity.org/2020/formulas/physics/college/b04sdnhbr9jkmkc24bde4046qwck9rtu5j.png)
![T = 6.147* 10^(4) years](https://img.qammunity.org/2020/formulas/physics/college/eo5jjiczqsnlfsm1s65ufi8kc7vvyebwfg.png)