Question

What is the path of an electron moving at 4 000 m/s perpendicular to a magnetic field of 1.5 T? (me = 9.11 x 10^-31kg)

Answer 1

`15.18* 10^(-9) m`

Step-by-step explanation:

Radius of the path of electron which is moving perpendicular to magnetic field is defined as,

`r=(mv)/(qB)`

Here, m is the mass of electron, v is the velocity of electron, q is the charge on electron, and B is the magnetic field.

Given that, the velocity of electron is,
`v=4000m/s`.

And the magnetic field is
`B=1.5T`.

And the mass of electron is,
`m=9.11*10^(-31)kg`

And the charge on electron is,
`q=1.6* 10^(-19)C`

Put all these values in radius equation,

`r=(9.11*10^(-31)kg* 4000m/s )/(1.6* 10^(-19)C* 1.5T)\\r=15.18* 10^(-9) m`

Therefore, the path radius of a moving electron is
`15.18* 10^(-9) m`