Question

Two parallel plates are charged with 7.58*10^-9 C of charge. What must the area of the plates be to create an electric field of 47500 N/C? (Unit = m^2)

Answer 1

area of the plates is 0.01802 m²

Step-by-step explanation:

given,

charge between the plate = 7.58 × 10⁻⁹ C

electric field = 47500 N/C

E =
`(V)/(d)`

V = E× d

charge on the plate

Q = C V

Q =
`(\varepsilon _0 A)/(d)* V`

Q = ∈₀ × A × E

A =
`(Q)/(\varepsilon _0 E)`

A =
`(7.58 * 10^(-9))/(8.854* 10^(-12) * 47500)`

A = 0.01802 m²

hence, area of the plates is 0.01802 m²