Question

A newly discovered particle, the SPARTYON, has a mass 945 times that of an electron. If a SPARTYON at rest absorbs an anti-SPARTYON, what is the frequency of each of the emitted photons (in 1020 Hz)? The mass of an electron is 9.11×10^-31 kg.

Answer 1

`\\u =1166* 10^(20)Hz`

Step-by-step explanation:

We have given the rest mass of SPARTYON = 945 times of mass of electron

We know that mass of electron
`=9.11* 10^(-31)kg`

So mass of SPARTYON
`=945* 9.11* 10^(-31)=8608.95* 10^(-31)kg`

Speed of light
`c=3* 10^8m/sec`

According to Einstein equation energy is given by

`E=mc^2=8608.95* 10^(-31)* (3* 10^(8))^2=77480.55* 10^(-15)j`

Now according to planks's rule

Energy is given by

`E=h\\u` , here h is plank's constant
`h=6.6* 10^(-34)`

So
`77480.55* 10^(-15)=6.6* 10^(-34)\\u`

`\\u =1166* 10^(20)Hz`