Question

A torque of 12 N*m is applied to a solid uniform disk of radius 0.50 m. If the disk accelerates at 2.6 rad/s^2 what is the mass of the disk? A) 26 kg B) 25kg C) 17 kg D) 34 kg

Answer 1

mass = 36.92 kg

Step-by-step explanation:

We have given the torque
`\tau =12 N-m`

Radius of the disk r = 0.50 m

Angular acceleration
`\alpha =2.6rad/sec^2`

We know that torque is given by
`\tau =I\alpha` here I is moment of inertia and
`\alpha` is angular acceleration

So
`12=I* 2.6`

`I=(12)/(2.6)=4.6153kgm^2`

Moment of inertia is given by
`I=(1)/(2)mr^2`

`4.6153=(1)/(2)m0.5^2`

m = 36.92 kg

The given answer is not matched with this answer but after calculation i got m =36.92 kg