Question

What slit width is needed to produce a central maximum 15° wide for 600 nm light undergoing single slit diffraction?

Answer 1

The slit width is 2.31 μm

Step-by-step explanation:

Given that

Angle θ = 15°

Wavelength λ = 600 nm

We know that relationship between slit width and wavelength

`w=(\lambda )/(sin\theta )`

Now by putting the values

`w=(\lambda )/(sin\theta )`

`w=(600 )/(sin15^(\circ) )`

w=2318.22 nm

w= 2.31 μm

So the slit width is 2.31 μm