Question

A convex security mirror has a radius of curvature of 12.0 cm. What is the magnification of a pare 3.0 m from the mirror?

Answer 1

magnification will be -0.025

Step-by-step explanation:

We have given the radius of curvature = 12 cm

And object distance = 3 m

So focal length
`f=(R)/(2)=(12)/(2)=6cm`

Now for mirror we know that
`(1)/(f)=(1)/(u)+(1)/(v)`

So
`(1)/(0.06)=(1)/(3)+(1)/(v)`

`16.66-0.333=(1)/(v)`

v = 0.750 m

Now magnification of the mirror is
`m=(-v)/(u)=(-0.750)/(3)=-0.025`