Question

An all-electric home uses approximately 1760 kWh of electric energy per month. How much uranium-235 would be required to provide this house with its energy needs for one year? Assume 100% conversion efficiency and 208 MeV released per fission.

Answer 1

mass of U 235 is 8.92 ×
`10^(-4)` gram

Step-by-step explanation:

given data

electric energy = 1760 kWh per month

energy u 235 = 208 MeV

to find out

mass of u 235

solution

we know here energy consume in a year is

energy consume = 1760 × 10³ ×3600 × 12

energy consume = 7.603 ×
`10^(10)` J

and

now we find no of u235 atom by burn require energy is

that is = energy consume / energy

= 7.603 ×
`10^(10)` / ( 208 × 1.6 ×
`10^(-13)` )

= 2.285 ×
`10^(18)`

and we know 1 mole of u235 = 6.02 ×
`10^(23)` atoms

so mass of U235 is

mass = 2.285 ×
`10^(18)` / ( 6.02 ×
`10^(23)` )

mass of U 235 = 8.92 ×
`10^(-4)` gram