Question

A fighter plane is flying overhead at mach 1.50. What angle does the wave front of the shock wave produced make relative to the plane's direction of motion (in degrees)?

Answer 1

θ = 41.80°

Step-by-step explanation:

Given that

Mach number M= 1.5

We know that

M = u/c

Where c is the velocity of sound and u is the speed of plane

c= 340 m/s

So

u = 1.5 x 340 m/s

u = 510 m/s

We know that

`sin\theta =(c)/(u)`

Now by putting the values

`sin\theta =(c)/(u)`

`sin\theta =(340)/(510)`

θ = 41.80°

So the angle will be 41.80°.