Answer:
30.93 m/s
Step-by-step explanation:
Given that, the speed of stolen car is,
![v_(s) =108km/hr\\v_(s) =108* (5)/(18)m/s\\ v_(s) =30m/s](https://img.qammunity.org/2020/formulas/physics/college/orlbigug9zyb4bv0hhdldr9h4e3sjw0pvv.png)
As policeman start chasing the stolen car after 60 seconds.
Now suppose the speed of policeman car is,
![v_(p)](https://img.qammunity.org/2020/formulas/physics/college/cql1xhlfrjltvrvc77mi6w4vmoyuezxhyw.png)
The policeman catches the stolen car at a distance of,
![S=60km\\S=60000m](https://img.qammunity.org/2020/formulas/physics/college/vb8te7qzwhu06tofptvh98zh9xl7tq65wa.png)
Now the distance covered by the policeman in time t is
![v_(p)* t](https://img.qammunity.org/2020/formulas/physics/college/a0y533czhr7rz0hr1nfuxgp7hbsfwasac4.png)
And the distane cover by the thief in stolen car in time(t+60s) is
.
And these distances are equal and they are equal to 60000 m.
Therefore,
![v_(p)* t=v_(s)* (t+60sec)=60000m](https://img.qammunity.org/2020/formulas/physics/college/sw13x82ozi9deswq7x0m4w6ygvpnlsnjel.png)
Therfore,
![v_(s)* (t+60sec)=60000m\\30m/s* (t+60sec)=60000m\\(t+60s)=2000s\\t=1940s](https://img.qammunity.org/2020/formulas/physics/college/nd0o6y18dk623gms1x22w6yjmcdmz6cc3r.png)
Now use this value to solve for minimum speed of policeman's car.
![v_(p)* 1940=60000\\v_(p)=30.93 m/s](https://img.qammunity.org/2020/formulas/physics/college/ni60pkvzcwjtzah2f3fw8pavfp5v71t778.png)
Therefore minimum speed of policeman's car is 30.93 m/s.