Answer:
The induced voltage in the Secondary is 18 volt.
Step-by-step explanation:
Given that,
Voltage = 120 volt
Number of turns in primary = 500
Number of turns in secondary = 75
We need to calculate the induced voltage in the Secondary
Using relation number of turns and voltage in primary and secondary

Where,
= Number of primary coil
= Number of secondary coil
= Voltage of primary coil
= Voltage of primary coil
Put the value into the formula



Hence, The induced voltage in the Secondary is 18 volt.