Question

X-rays with a wavelength of 0.0711 nm create a diffraction pattern when they pass through a protein crystal. If the angular spacing between adjacent bright spots (m=0 and m=1) in the diffraction pattern is 28.9°, what is the average spacing between atoms in the crystal?

Answer 1

The average spacing between atoms in the crystal is
`1.47*10^(-10)\ m`.

Step-by-step explanation:

Given that,

Wavelength = 0.0711 nm

Diffraction pattern = 28.9°

We need to calculate the average spacing between atoms in the crystal

Using formula of distance

`d\sin\theta=m\lambda`

`d=(m\lambda)/(\sin\theta)`

Here, m = 1

Put the value into the formula

`d=(1*0.0711*10^(-9))/(\sin28.9)`

`d=1.47*10^(-10)\ m`

Hence, The average spacing between atoms in the crystal is
`1.47*10^(-10)\ m`.