Question

5. Your friend tosses a ball into the air. The equation h = -5ť + 30t +10 models the height,

h, of the ball t seconds after it was thrown.
241-9) (10) -301 /25.4
a. How long was the ball in the air?
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Answer 1

6.3s.

Step-by-step explanation:

The height h is given by:

`h(t)=-5t^2+30t+10`

Setting the height h = 0 and using the quadratic formula to solve for t:

`0=-5t^2+30t+10\\0=t^2-6t-2\\t_1=3-√(11)= -0.3s\\t_2=3+√(11)=6.3s`

t₁ is physicly meaningless.