Find the area of the figure. A. 71 in2 B. 70 in2 C. 72 in2 D. 58.5 in2

Question

asked Jan 27, 2020 159k views

1 Answer

Dime · Answer 1 · 2020-02-01T04:02:07+0000

For this case we have that by definition, the area of a square is given by:

A = l ^ 2

In this case, the square is 9 \ in side, then:

$A = 9 ^ 2\\A = 81 \ in ^ 2$

On the other hand, the area of a triangle is given by:

$A = \frac {1} {2} b * h$

Where:

b: It is the base of the triangle

h: It is the height

We have according to the figure that:

$b = 9-5 = 4 \ in\\h = 9-4 = 5 \ in$

So:

$A = \frac {1} {2} (4 * 5)\\A = \frac {20} {2}\\A = 10 \ in ^ 2$

Finally, the area of the figure is:

$A_ {t} = 81 \ in ^ 2-10 \ in ^ 2\\A_ {t} = 71 \ in ^ 2$

Answer:

$A_ {t} = 71 \ in ^ 2$