Answer:
The answer to your question is: 0. 55 M
Step-by-step explanation:
Data
H = 1
C = 12
O = 16
MW of glucose = (1x12) + (12x 6) + (16x6) = 12 + 72 + 96 = 180 gr
We have a solution 10% of glucose that means 10 g of glucose and 100 ml of solution
Also Molarity = # moles / liters
180 g of glucose -------------- 1 mol
10 g ----------------------------- x
x = 10 x 1/180 = 0.055 moles
Molarity = 0.055 /0.1 liters = 0.55 M